九宫格

# #九宫格：# 1|2|3# 4|5|6# 7|8|9# 横排相加=15，竖排相加=15，两对角相加等于15num=[]for i in range(1,10):    num.append(i)#遍历x、y，当x!=y时，再遍历z,x!=z,y!=z,三个数就都不一样L=[(x,y,z) for x in num for y in num if x!=y for z in num if x!=z and y!=z and x+y+z==15]for L1 in L:    for L2 in L:        if set(L1) & set(L2):               #set集合，取出的第一排不能等于第二排            continue        for L3 in L:            if set(L1) & set(L2) & set(L3): #第一、二、三排都不等                continue            elif L1[0]+L2[0]+L3[0] != 15:   #竖排不等的话就跳过,横排肯定是相等的，所以不用判断                continue            elif L1[1]+L2[1]+L3[1] != 15:                continue            elif L1[1]+L2[1]+L3[1] != 15:                continue            elif L1[0]+L2[1]+L3[2] != 15:   #两对角不等的话就跳过                continue            elif L1[2]+L2[1]+L3[0] != 15:                continue            else:                print('''                    {0}|{1}|{2}                    {3}|{4}|{5}                    {6}|{7}|{8}                    '''.format(L1[0],L1[1],L1[2],L2[0],L2[1],L2[2],L3[0],L3[1],L3[2]))

函数入门

判断某天为某年的第几天：

dat = input('Enter a certain year and a certain day，format: yyyy-mm-dd ：')year=int(dat[0:4])month=int(dat[5:7])day=int(dat[8:])Leap_year=1 #先定义不是闰年if year % 4 == 0 and year % 100 != 0:       Leap_year=0   #判断是闰年elif year%400 == 0:    Leap_year = 0    #判断是闰年else:    Leap_year = 1if Leap_year== 0:   #是闰年，2月份就是29天    ms = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]else:    ms = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]days=0if month in range(1,13):    for i in range(month-1):        days+=ms[i]    print('{0} is this years {1} days'.format(dat,(days+day)))